A of the polygon by -4, B, C, D, E, and the ext. If four quantities of the same hind are in pro- portion, they wUL he in proportion hy alternation; thai is, the first term will he to the third as the sec- ond to the fourth. If the diagonals of a trapezoid are equal, the c D trapezoid is isosceles. The length of the circumference is therefore the limU of the length of the perimeter as the number of sides of the inscribed figure is indefinitely increased. Two quantities that can be expressed in integers in terms of a common unit are said to be commensurable. All right angles are equal. Sup supplementary.
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Hence, All straight lines which pass through the same point in the same direction coincide, and form hut one line. Two sides of a triangle and the angle opposite one of them being given, to construct the triangle. The perpendiculars dropped from the middle point of the base of an isosceles triangle upon the legs are equal. Pboposition XXXI. So that, if any number of points be put together, they will coincide and form a single point. The problem is impossible when one side is equal to or greater than the sum of the other two. If two circles intersect, and a secant is drawn through each point of intersection, the chords which join the extremities of the secants are parallel. To mecLSure a quantity of any kind is to find how many times it contains another known quantity of the same kind.
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